Kenneth S. answered • 05/02/17

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Center is (-1,3) as revealed in the (x-h)

^{2}and (y-k)^{2}expressions.For this type of hyperbola, the transverse axis runs horizontally (through the center) since the y-related terms are subtracted from the x-related terms in this format.a=3(square root of x-related denominator) and b = 4, and b

^{2}= c^{2}- a^{2}. This means that c = 5.Foci are 5 units to the left and to the right of the center, therefore their coordinates are (-6,3) and (4,3).

In point-slope form, the equations of the asymptotes are y-3 = ±(4/3)(x+1).

I leave something for you to do: figure the coordinates of the two vertices.

*Hint: easy if you make a sketch showing transversal running through the designated Center.*