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A hyperbola is centered at C=(3,7). The vertices are (9,7) and (-3,7). The slopes of the asymptotes are m=+-5/6

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1 Answer

If you make a plot of the veritices and the center, you find----
The axis of the hyperbola is horizontal.
Since center is (3,7)
Since equation of asymptote is +-5/6 =. +-b/a
So, b= 5
So, the equation of hyperbola is 
  ((x-3)^2)/36.   -  ((y-7)^2)/25. =1


This answer seems to be wrong, is there anything else it can be? It says the answer needs to be entered in the form (x-h)^2/a^2-(y-k)^2/b^2=1
Yes, the answer is in the same form and correct.