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center and radius

 State the center and the radius of the circle represented by the equation. show all work 
 
(x-4)^2+(y+6)^2=64

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Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
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(x-4)^2 + (y+6)^2 = 64
 
(x–4)^2 + (y–(-6))^2 = 8^2
 
Center: (4,–6)
Radius: 8
 
Because:
 
Using Pythagorean Theorem you can find the equation of a circle centered at origin with radius r as:
 
x^2 + y^2 = r^2
 
Then you can translate it <h,k> (h units in x-direction, k units in y-direction) to get:
 
(x – h)^2 + (y – k)^2 = r^2