State the center and the radius of the circle represented by the equation. show all work

(x-4)^2+(y+6)^2=64

State the center and the radius of the circle represented by the equation. show all work

(x-4)^2+(y+6)^2=64

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(x-4)^2 + (y+6)^2 = 64

(x–4)^2 + (y–(-6))^2 = 8^2

Center: (4,–6)

Radius: 8

Because:

Using Pythagorean Theorem you can find the equation of a circle centered at origin with radius r as:

x^2 + y^2 = r^2

Then you can translate it <h,k> (h units in x-direction, k units in y-direction) to get:

(x – h)^2 + (y – k)^2 = r^2

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