Solve the following

Question

Solve the following!

1. Divide the 2000 by the product of 8 and 5.

2. Subtract the product of 25 and 8 from the sum of the least 5 digit even number and the greatest 4 digit number.

3. Multiply 345 by 25 and divide the product by the sum of 8 and 7.

4. Add the sum of 20,376 and 24 to the product of 874 and 18.

Answer 1

Sure, I can help you with those calculations:

1. 20008×5=200040=508×52000​=402000​=50
2. Let's break this down step by step:
3. Least 5-digit even number: 10000
4. Greatest 4-digit number: 9999
5. Sum of these: 10000+9999=1999910000+9999=19999
6. Product of 25 and 8: 25×8=20025×8=200
7. Subtracting the product from the sum: 19999−200=1979919999−200=19799
8. 345×258+7=862515=5758+7345×25​=158625​=575
9. 20376+24+874×18=20376+24+15732=3613220376+24+874×18=20376+24+15732=36132

So, the results are:

1. 50
2. 19,799
3. 575
4. 36,132

Answer 2

1 2000/40= 50

2 10000+9999 - 200 = 19799

3 345(25)/56 = about 154

4 20400/847(18)= about 1.338

use a calculator on last two, or some tedious long division