Mark M. answered 05/02/23
Mathematics Teacher - NCLB Highly Qualified
With replacement
(7/12)(5/12) = ?
Without preplacement
(7/12)(5/11) = ?
Hanna K.
asked 05/02/23Michelle has a purse that contains 7 silver coins and 5 gold coins. She draws one coin at random and then draws a second coin. What is the probability that the first coin is gold and the second coin is silver if the coins are drawn with replacement and without replacement?
Mark M. answered 05/02/23
Mathematics Teacher - NCLB Highly Qualified
With replacement
(7/12)(5/12) = ?
Without preplacement
(7/12)(5/11) = ?
Jarrett L. answered 05/02/23
Experienced Middle School and High School Math and SAT Tutor
Hi Hanna.
If the coins are drawn WITHOUT replacement:
The probability of the first coin drawn being gold is 5/12 and the probability that the 2nd coin drawn being silver is 7/11. Therefore the probability of both together is 5/12 * 7/11 or 35/132
If the coins are drawn WITH replacement:
The probability of the first coin drawn being gold is 5/12 and the probability that the 2nd coin drawn being silver is 7/12. Therefore the probability of both together is 5/12 * 7/12 or 35/144
Hope this helps!
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