Peter R. answered • 04/28/23
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Experienced Instructor in Prealgebra, Algebra I and II, SAT/ACT Math.
The four consecutive integers can be x, x + 1, x + 2, and x + 3.
Three times the sum of the 1st and 2nd is 3(x + x + 1). 15 less than the 4th is x + 3 - 15
So the equation is 3(2x + 1) = x - 12
6x + 3 = x - 12 -> 5x = -15
So x = -3; x + 1 = -2; x + 2 = -1; x + 3 = 0 (Didn't say they had to be positive or non-zero!)
Check: 3(-3 + -2) = -15 and 0 - 15 = -15 (OK)
Peter M.
The consecutive odd integers are -3, -1, 1, and 3. Check: 3(-3 + -1) = 3(-4) = -12 and -12 + 15 = 3.
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04/29/23
Peter R.
tutor
Thank you for your correction Peter. I missed that vital piece of information. And to think that I've corrected others for similar oversights in the past!
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04/29/23
Peter M.
The problem asks for four consecutive odd integers, not four consecutive integers.04/29/23