Finding consecutive numbers, algebra

Question

Find four consecutive even integers such that if the sum of the first and third is multiplied by 3, the result is 28 less than five times the fourth.

Answer 1

3(x+x+4) = 5(x+6) -28

3x+3x +12 = 5x +30 -28

6x -5x = 2 -12

x = -10

x+2 = -8

x+4 = -6

x+6 = -4

the even consecutive integers are

-10, -8, -6, -4