I REALLY NEED HELP ON THIS ASAP PLEASE!

Question

The equation N(t)= 1200/1 + 199e^-0.625t models the number of people in a school who have heard a rumor after t days.

a) How many people started the rumor?

b) To the nearest tenth, how many days will it be before the rumor spreads to half the carrying capacity?

Answer 1

at t=0 N(t)=6

since 1200 is maximum of N(t) ,,,,,,1/2 of that=600

600=1200/(1+199e^-.625t)

199e^-.625t=1

-.625t=ln(1/199)=-ln(199)=-5.293

t=8.5 days