
Niemah E. answered 05/15/24
Experienced Elementary School Tutor Concentrated in Language Arts
Hi Richard!
According to the question, the amount accumulated in the account is:
A = $50,000
Rate of interest is R = 3% = 0.03 annually.
If interest is compounded monthly the periodic interest rate is:
I = R / 12 = 0.03 / 12 = 0.0025
The period of payments is:
N = 9 years = 9 × 12 = 108 months
As payments are deposited at the end of the period so given annuity is an ordinary annuity. The amount deposited in an ordinary annuity to have an accumulated value is given by:
C = A × i / (1+i)^n - 1
Substitute the values and solve for periodic deposits. The amount need to be deposited at the end of each month is:
C = 50,000 × 0.0025 / (1 + 0.0025)^108 - 1
C = $403.85
The amount need to be deposited at the end of each month is:
$403.85