A quadratic function has these characteristics. Please determine the following...

Question

Question #1:

A quadratic function has these characteristics:

x = 1 is the equation for the axis of symmetry.

x = –1 is an x-intercept.

y = –4 is the minimum value.

Determine the y-intercept of this parabola.

Please make your answer easy to understand...thank you. :)

Answer 1

y = (x+1)(x-3) the x intercepts are -1 and 3, both equidistant from x=1, the axis of symmetry, both 2 away

y = x^2 -2x -3 set x = 0 and y= -3 = the y intercept = the point (0, -3)

it's an upward opening parabola with vertex (1, -4) = minimum point. the x coordinate of the vertex is the same as x=1, the axis of symmetry.

Answer 2

y = (x+1)(x-3) the x intercepts are -1 and 3, both equidistant from x=1, the axis of symmetry, both 2 away

if -1 and 3 are zeros, then x+1 and x-3 are factors

y = x^2 -2x -3 set x = 0 and y= -3 = the y intercept = the point (0, -3)

it's an upward opening parabola with vertex (1, -4) = minimum point. the x coordinate of the vertex is the same as x=1, the axis of symmetry.

plug x=1, y=-4 into the equation

-4 = 1^2 -2(1) -3

-4 = 1 -2 -3 = -4