If a 0.3911 gram sample of 95% sodium bicarbonate is titrated with 0.9387 N sulfuric acid, what volume of the acid is needed to produce an endpoint?

Question

The answer should be rounded in 2 decimal places and for consistency of the atomic weights, round up to 1 decimal place. Example: Chlorine is 35.5 and Oxygen is 16. Sulfur is 32.1. etc.

Answer 1

Looking at the balanced reaction, we have...

2NaHCO₃ + H₂SO₄ ==> Na₂SO₄ + H₂O + CO₂

moles of NaHCO₃ present = 0.3911 g x 95% x 1 mol / 84.0 g = 0.004423 moles

moles H₂SO₄ required = 0.004423 mols NaHCO₃ x 1 mol H₂SO₄ / 2 mols NaHCO₃ = 0.00221 mols H₂SO₄

volume H₂SO₄ = 0.00221 mols x 1 L / 0.9387 mols = 0.002356 L = 2.36 mls