Inactive Tutor answered 01/10/22
mv2/2 = kx2/2; k = mv2/x2 = 0.256kg·(0746m/s)2/(0.182m)2 = 4.3 N/m
Alex J.
asked 01/10/22A spring is suspended from a ceiling and a 256-g mass is attached to it and pulled down to stretch the spring by 18.2 cm. The mass is released and travels through the equilibrium position with a speed of 0.746 m/s. Calculate the force constant of the spring.
Inactive Tutor answered 01/10/22
mv2/2 = kx2/2; k = mv2/x2 = 0.256kg·(0746m/s)2/(0.182m)2 = 4.3 N/m
Roger N. answered 01/10/22
. BE in Civil Engineering . Senior Structural/Civil Engineer
Roger N.
01/11/22
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Alex J.
Hello, Thank you for the video! At the third position wouldn't the mass have gravitation potential energy as well as kinetic energy or will it only have kinetic energy?01/11/22