How many grams of NO will be produced from 75.1 g of NO₂ reacted with excess water in the following chemical reaction? 3 NO₂(g) + H₂O(l) → 2 HNO₃(g) + NO(g)

Answer 1

3NO₂(g) + H₂O(l) ==> 2HNO₃(g) + NO(g) ... balanced equation

Use the stoichiometry of the balanced equation along with dimensional analysis to find the grams of NO produced.

molar mass NO₂ = 46.0 g / mol

molar mass NO = 30.0 g / mol

75.1 g NO₂ x 1 mol NO₂ / 46.0 g x 1 mol NO / 3 mol NO₂ x 30.0 g NO / mol = 16.3 g NO