J.R. S. answered 11/21/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Let me abbreviate tiamulin hydrogen fumarate as THF
12.5% w/v means 12.5 g THF per 100 mls of solution.
We want 227 mg of THF per gallon of solution.
We need to make a few conversions to find how many gallons of THF can be made.
Conversion factors:
1000 ml = 1 L
3.785 L = 1 gallon (gal)
What we have:
12.5 g TFH / 100 ml = 125 g / L x 3.785 L / 1 gal = 33.0 g / gal = 33,000 mg / gal
H2O as diluent = 0 mg THF / gal
What we want:
227 mg / gal
We can use V1C1 = V2C2 to find V2
V1 = 1 L x 1 gal / 3.785 L = 0.264 gal
C1 = 33,000 mg / gal
V2 = ? gal
C2 = 227 mg / gal
(0.264 gal)(33,000 mg/gal) = (V2)(227 mg/gal)
V2 = 38.38 gallons = 38.4 gallons can be prepared
or
Using alligation:
Have.........Need........Parts
0..............................32,773
................227...................
33,000......................227
So, 227 parts would = 1 liter and 32,773 parts would = 144.4 L = ~ 38.2 gallons