Line g contains A(–4, 3) and B(3, 1). Line h contains S(–1, –1) and T(6, y). In order for g to be parallel to h, what is the y-coordinate of T?

Question

A)-3

B)-1

C)0

D)1

Answer 1

2/7=(y-1)/7 this is the condition that lines g and h are parallel: tangents of angles between lines and x should be equal.

so y=3 as a absolute value of the cathetus for the angle between line h and x.

But as a y coordinate it should be -3 otherwise the line h will cross the line g.

So the answer is T(6, -3)

Answer 2

Solution:

For lines h and g to be parallel, their slopes must be equal.

Find the slope of line g, m_g = ( 1-3)/(3-(-4)) = (1-3)/(3+4) = -2/7

The slope of line h is m_h = m_g = -2/7 = ( y-(-1))/ (6-(-1)) = (y+1) / ( 6+1) = (y+1)/ 7 ,

-2/7(7) = y+1 , -2 = y+1 , y = -2-1 =-3

Ckeck:

m_h = (-3-(-1)) / (6-(-1)) = (-3+1)/(6+1) = -2/7 = m_g Therefore checks and y coordinate = -3

Answer is A) -3

Answer 3

Parallel lines have the same slope.

So, (1 - 3) / (3 - (-4)) = (y - (-1)) / (6 - (-1))

Solve for y.