A car accelerates at 2.7 m/s/s for 5.4 s, reaching a speed of 18 m/s. During the period of acceleration, the car travels a distance of...

Question

A car accelerates at 2.7 m/s/s for 5.4 s, reaching a speed of 18 m/s. During the period of acceleration, the car travels a distance of...

I know how to find acceleration and velocity but I'm stuck. The answer is supposedly 58 m but I don't know how.

Answer 1

Initial Variables:

v_f = 18 m/s

t = 5.4 s

a = 2.7 m/s2

Finding Initial Velocity:

v_f = v_0 + a*t

v_0 = v_f - a*t = (18 m/s) - (2.7 m/s2)*(5.4 s)

v_0 = 3.42 m/s

Finding Distance Using Timeless Formula

v_f^2 = v_0^2 + 2*a*D

D = (v_f^2 - v_0^2) / (2*a)

D = (18^2 - 3.42^2) / (2*2.7)

D = 57.834 meters