Inactive Tutor answered 08/04/21
Work A1 agaist resistance A1 = - mgh = - 10kg·9.8 m/s2·5m = 490 J
Then if we move it back we have to compansate work against resistance and move up to give potential energy. So, A = A1 + mgh = 490j + 490J = 980 J
Gabrielius T.
asked 08/04/21A sled of mass 10 kg went down from a hill of height 5 m and stopped at the horizontal part of a road. Find the work done when dragging the sled up the hill. Answer is 1000 J
Inactive Tutor answered 08/04/21
Work A1 agaist resistance A1 = - mgh = - 10kg·9.8 m/s2·5m = 490 J
Then if we move it back we have to compansate work against resistance and move up to give potential energy. So, A = A1 + mgh = 490j + 490J = 980 J
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