
William W. answered 06/18/21
Experienced Tutor and Retired Engineer
Cost = cost of bulbs + cost of the electricity
Let C1 = cost of using the energy savings bulb and C2 be the cost of using the conventional bulb.
26W = 26/1000 kW = 0.026 kW and the electricity used by an energy efficient bulb is 0.026(10,000) kW-hrs = 260 kW-hrs.
100W = 100/1000 kW = 0.1 kW and the electricity used by a conventional bulb is 0.1(10,000) kW-hrs = 1000 kW-hrs.
1 energy efficient bulb is required for 10,000 hrs
10000/750 = 13.333 = 14 conventional bulbs are required for 10,000 hrs.
C1 = (cost of 1 bulb) + (cost of electricity) = 4.20 + 260(0.20) = $56.20
C2 = (cost of 14 bulbs) + (cost of electricity) = 14(0.54) + 1000(0.20) = $207.56
Cost savings in using energy efficient bulbs (for 10,000 hrs) = $207.56 - $56.20 = $151.36