What are the phenotypes, by sex, of their possible offspring?

Question

Brown eyes (B) is dominant to blue eyes (b) in people. Hemophilia is a sex linked trait (X^h) that is recessive to normal blood clotting (X^H). A heterozygous brown-eyed woman who is a carrier of the hemophilia gene marries a blue-eyed man who has normal blood clotting.

Answer 1

Female offspring have a:

-50% probability of being brown-eyed with normal clotting

-50% chance of being blue-eyed with normal clotting

Male offspring have a:

-25% chance of being brown-eyed with normal clotting

-25% chance of being blue-eyed with normal clotting

-25% chance of being brown-eyed with hemophilia

-25% chance of being blue-eyed with hemophilia

Since the dad does not have hemophilia, and it is an x linked trait, this means that his x will be X^H. Therefore, he will give his daughters a non mutated x chromosome. In addition, the mom is only a recessive carrier, which means that even if she gives her daughters her mutated x chromosome, they will only be carriers for hemophilia, since they have a healthy x chromosome from dad.

For the sons however, they only receive one x chromosome, and that x chromosome always comes from mom. If they get her mutated chromosome, they will have hemophilia.

In terms of figuring out the eye color, I drew a simple punnet's square and determined that there is a 50% chance of either eye color. When determining the probability of two events occuring simultaneously, you multiply the probabilities by each other. Therefore, since males have a 50% chance of being brown-eyed, and a 50% chance of being blue-eyed in addition to a 50% chance of having hemophilia and a 50% chance of having normal blood clotting, you simply multiply 1/2 by 1/2 to get their probabilities of 25%.

Please upvote if correct