Hello, Laura,
I don't have time to answer all the questions, but I'll offer what I can.
a. write the balanced chemical equation for the given reaction above.
I came up with: 2C6H12 + 5O2 = 2H2C6H8O4 + 2H2O
b. is the reaction exothermic or endothermic? Explain.
It is an oxidation reaction, so I suspect it is exothermic, but I did not do a detailed analysis to say for certain.
c. how many grams of Adipic acid will be formed if 25.0g cyclohexane is
reacted with 15.0g oxygen gas?
We need to identifiy which reactant may be limiting. Convert both the cyclohexane and oxygen into moles:
C6H12 25.0grams/84.1 g/mole = 0.297 moles
O2 15.0 grams/32 g/mole = 0.469 moles
The ratio of oxygen to cyclohexane is 5/2, according the the balanced equation. There isn't enough oxygen to react with all of the cyclohexane, so oxygen is the limiting reagent. We'll base our prediction of products by assuming all of the O2 is consumed. They equation says we'll get 2 moles of adipic acid for every 5 moles of O2. So let's assume all 0.469 moles of O2 react. That means we'll produce 2/5 that amount of adipic acid:
(0.469 moles O2)*(2 moles adipic acid/5 moles O2) = 0.075 moles nylon
The molar mass of nylon is 146 g/mole, so that means we have (0.075 mole)*(146g/mole) = 3.37 grams nylon
d. what is the limiting reactant? the excess reactant?
O2 is limiting, as per the above. Cyclohexane is the excess reagent.
e. how much is left unreacted in the chemical reaction?
We only needed o.188 mole C6H12, so 0.110 mole remains (multiply by 84.1 g/mole) if grams is the required unit).
f. draw a complete enthalpy profile diagram for the above chemical
reaction.
Sorry, I don't have the time and I really don't know what is meant, other than to identify the enthalpies of both the starting and ending reagents, adjusted to the actual conditions of the reaction (i.e., the remaining cyclohexane will have an enthalpy. I don't see any of the enthalpies listed in the question. I hope they are listed in your texbook, but they can often be found online, also.
Bob
