Inactive Tutor answered 06/01/21
(a) radial acceleration an = IaIcos30° = 16.5cos30° = 14.29 m/s2 (tovard to center);
(b) v2/r = Ian; v = √rIanI = √(14.29m/s2·4.40)m = 7.93 m/s;
(c) at = IaIcos60° = 16.5·0.5 = 8.25 m/s2 in direction of motion
Jeremy A.
asked 06/01/21This figure (|a| = 16.5 m/s^2) represents the total acceleration of a particle moving clockwise in a circle of radius r = 4.40 m at a certain instant of time.

(a) For that instant, find the radial acceleration of the particle.
: _____________m/s2 (toward the center)
(b) For that instant, find the speed of the particle.
: _____________ m/s
(c) For that instant, find its tangential acceleration.
: _____________m/s2 (in the direction of the motion)
Inactive Tutor answered 06/01/21
(a) radial acceleration an = IaIcos30° = 16.5cos30° = 14.29 m/s2 (tovard to center);
(b) v2/r = Ian; v = √rIanI = √(14.29m/s2·4.40)m = 7.93 m/s;
(c) at = IaIcos60° = 16.5·0.5 = 8.25 m/s2 in direction of motion
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