Please Read Question Below!

Question

A member of the basketball team jumps straight up and their center of mass has a speed of 3.32 m/s as they leave the court. How high above this point is their center of mass at the following times? (Enter your answers in m. Ignore the effects of air resistance, and assume the initial height of their center of mass is at y = 0.)

t(s) y(m)

t₁ = 0.100 ____

t₂ = 0.239 ____

t₃ = 0.339 ____

t₄ = 0.439 _____

Answer 1

s = ut + 0.5at²

u = 3.32 (initial vertical speed)

a = -9.81 (acceleration due to gravity downwards)

substitute the four values of t into this and calculate s