A foreign automobile manufacturer claims that its sports car will accelerate from rest to a speed of 43.0 m/s in 7.50 s.

Question

(a) Determine the magnitude of the average acceleration of the car (in m/s²).

b) Assume that the car moves with constant acceleration. Find the distance (in m) the car travels in the first 7.50 s.

c) What is the speed of the car (in m/s) 10.0 s after it begins its motion if it continues to move with the same acceleration?

Answer 1

(a) 43 / 7.5 = 5.73 m/s/s

(b) s = ut + 0.5at²

u = 0, a = 5.73, t = 7.50 so s = 161.16 m

(c) 10 x 5.73 = 57.3 m/s