I need help solving with jules. Please and thank you!

Question

40g of water is placed in a calorimeter at an initial temperature of 20.2˚C. After the addition of a sample of warm metal, the final temperature of the water is 23.6˚C. How much heat did the water absorb from the metal sample? (The specific heat of water is 4.184 J/(˚C*kg)

 

Answer in Joules to 1 decimal place.

Answer 1

q = mCT

q = heat = ?

m = mass of water = 40 g

C = specific heat of water = 4.184 J/gº

∆T = change in temperature = 23.6º - 20.2º = 3.4º

Solving for q we have...

q = (40 g)(4.184 J/gº)(3.4º) = 569.0 joules