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Question

A 12g sample of hot metal is placed in a calorimeter with a known mass of water. It is determined that the metal releases -50J of heat in the process. The change in temperature of the metal (∆T) is -6.53˚C. What is the specific heat of the metal?

Answer the question to 2 decimal places.

Answer 1

q = mC∆T

q = heat = 50 J

m = mass of metal = 12 g

C = specific heat of metal = ?

∆T = change in temperature = 6.53º

Solving for C, we have

C = q / (m)(∆T) = 50 J / (12 g)(6.53º)

C = 0.64 J/gº