physics question

Question

A tangential force of 360 N acts for a time of 5.0 seconds at the edge of a potter’s wheel (solid cylinder or disc) with radius 50.cm and mass 45kg. What is the change in its angular velocity?

[ans: ∆ω = 160 rad/s]

Answer 1

Let Torque = T = F*r= 360*.5=180 N-m ... We know that T*delta t = I delta w ... delta t= 5 sec. I = .5mr²=.5*45*.25. Solving for delta w=180/22.5/.25=160 rad/sec.