
Lia K.
asked 05/16/21Please help with question I really don't understand!
- The door prizes at a dance are gift certificates from local merchants. there are four $10 certificates, five $20 certificates, and three $50 certificates. The prize envelopes are mixed together in a bag and are drawn at random.
a) Use a tree diagram to illustrate the possible outcomes for selecting the first two prizes to be given out.
Please show all steps for this question and a explanation because I really don't understand why the tree diagram looks like that from the answer.
2 Answers By Expert Tutors

Dayv O. answered 05/16/21
Caring Super Enthusiastic Knowledgeable Algebra Tutor
Lia, On Left side of paper in middle of page draw a dot and three lines with arrows. top line going angle up middle line straight and bottom line anglingi down. Maybe two inches length each for the lines.
top line is labelled $10. and probability 4/12, mdidlle line $20 and probability 5/15, bottome line $50 and probability 3/12. That represents prize one being chosen.
Now on the top line where arrow is, draw thre lines one angling up (label that line $10 and probability 3/11), one straight (label that one $20 and probability 5/11) anf one angling down (label that one $50 and probability 3/11).
on the original middle line where arrow is draw three lines, $10 probability 4/11, $20. probability 4/11,
and $50 probability 3/11.
on original bottom line draw three lines from where the arrow is. $10 probability 4/11, $20. probability 5/11, and $50 probability 2/11.
The second set of lines indicate the proibability of the outcome based on the previous outcome.
To go a bit further ---what is probability the first two prize are $10 and $10, answer = (4/12)*(3/11). What is probability of first two prizes being $10 and $20, answer=(4/12)*(5/11). What is probability of first two prizes being $10 and $50, answer=(4/12)*(3/11). What is probabiliry of first two prizes being $20 and $10, answer=(5/12)*4/11) and you can continue down the other outcomes and multiply the probabilities together.
Lia K.
Thank you so much, but for the branches why do you have to add all three of the prizes, for example, for the $10 branch, don't you have to add the other two branches, not including the $10? (so two all together)? And for getting the third prize, would you mind providing a little more detail? I'm still a little confused, like why do you have to do that when the third prize is being chosen, if that makes sense.05/16/21

Dayv O.
in an hour, I'll respond05/16/21

Dayv O.
Okay, let's say 1st envelope chosen is $10. (probability=4/12), the choices for the second envelope now number in total 11, 3 each $10., 5 each $20, and 3 each $50. There has to be three branches off the first pick=$10. branch. Same with first choice=$20., there needs to be three new branches, same with first choice=$50. there needs to be three new branches. Hint, for third choice total envelopes available are 10 since two have been used already.05/17/21
Lia K.
Originally the answer would just stop at the 2nd prize being chosen, right? Since that's what the question is asking for.05/17/21

Dayv O.
si05/17/21

Dayv O.
lia, at completion of two envelope choices there are 9 possibilities of exact first choice, exact second choice. One interesting one is first=$50 and second=$50, the probability of that happening is (3/12)*2(/11)=6/131=less than .05. So it is only less than 1/20 times the first envelope picked and the second envelope picked are both $50.05/17/21

Mark M. answered 05/16/21
Mathematics Teacher - NCLB Highly Qualified
$10
$10 $20
$50
$10
$20 $20
$50
$10
$50 $20
$50
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Mark M.
Look for examples in your text book.05/16/21