
Mark M. answered 05/11/21
Mathematics Teacher - NCLB Highly Qualified
101C98 x 101C3
[101! / (98!)(100 - 98)!] x [101! / (3!)(100 - 3)!]
[101(100)(99) / 3!] x [101(100)(99)) / (3!]
It is like that!
Sam L.
asked 05/11/21f) C(101, 98) x C(101, 3)
The answer is supposed to be 27, 772, 222, 500.
Please explain the steps, because I do not understand them. Why is it like this??
C(101, 98) x C(101, 3) = [C(101, 3)]2 = (101·100·99/(6))2 = 27772222500
Mark M. answered 05/11/21
Mathematics Teacher - NCLB Highly Qualified
101C98 x 101C3
[101! / (98!)(100 - 98)!] x [101! / (3!)(100 - 3)!]
[101(100)(99) / 3!] x [101(100)(99)) / (3!]
It is like that!
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