Hi so um I need help with my homework and I have needed help for many hours please someone respond and help me as soon as possible

Question

1.) S   + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O

In the above equation how many moles of H2SO4 can be made when 56 moles of HNO3 are consumed?

2.) S   + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O

In the above equation how many moles of water can be made when 57 moles of HNO3 are consumed?

please help me by explaining and solving please

Answer 1

Hi Sydney R

First make sure you have balanced equations, if so then just use the moles in the equation as ratios to solve for unknown amount

1.) S   + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O

Says that 6 moles of Nitric Acid make one mole of Sulfuric acid you can also interpret that as for each mole of Sulfuric acid you need 6 moles of Nitric Acid

1 mole Sulfuric Acid/6 moles of Nitric Acid

1 mole Sulfuric Acid/6 moles of Nitric Acid = x moles of Sulfuric Acid/56 moles of Nitric Acid

Just cross multiply to find x

I get 9.3 moles of Sulfuric Acid

2.) S   + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O

Says 6 moles of Nitric Acid are consumed to yield 2 moles of Water, you can also state that

2 moles of Water are made when 6 moles of Nitric Acid are consumed

2 moles of Water/6 moles of Nitric Acid

2 moles of Water/6 moles of Nitric Acid = x moles of Water/ 57 moles of Nitric Acid

Just cross multiply to solve for x

I get 171 moles of Water

I hope this helps just send me a message if you have any questions.