
Mark M. answered 05/02/21
Mathematics Teacher - NCLB Highly Qualified
This is a poorly posed situation. Assuming that all of the goals could be anytime during the game, 28.
(0, 0), (0, 1), (0, 2), (0, 3)
(1, 0), (1, 1), (1, 2), (1, 3)
(2, 0), (2, 1), (2, 2), (2, 3)
...
...
...
(6, 0), (6, 1), (6. 2), (6. 3)
7 x 4 = 28