probability question involving cards

Question

1. As 4 cards are take out of a deck, what would the probability be if the 4th card is a RF card or a J, when the J of diamonds is the 1st card selected, 2nd the Q of hearts, 3rd three of diamonds.

would it be 4/49? thanks.

Answer 1

P(RF)=4/49

P(J)=3/49

P(RF and J)=1/49

P(RF or J)=P(RF)+P(J)-P(RF and J)=6/49

Maybe I misunderstand the question.

Let me rephrase it as I understand it.

4 cards are drawn without replacement from a standard deck.

The first 3 cards are J diamonds, Q hearts and 3 diamonds.

What is the probability that the 4th card is either a red face card or a J?

We agree that before the 4th card is drawn there are 49 cards left.

At that point:

P(RF)=4/49....K & Q of diamonds and J and K of hearts

P(J)=3/49.....J hearts, J spades, J clubs

P(RF and J) = 1/49.....only J hearts satisfies the condition

Then P(RF or J)=(4+3-1)/49 = 6/49

Please let me know if you still think my answer is incorrect.