
Yefim S. answered 04/29/21
Math Tutor with Experience
Probability to win in first game P1 = 4/(3 + 4) = 4/7
Probability to win in 2nd game P2 = 2/(2 + 3) = 2/5
4/7 = 20/35 > 14/35 = 2/5.
So I will pay 1st game because more chance to win
Sam L.
asked 04/28/211.which would you prefer to play,
a game with odds of 3:4 against winning or a game of odds of 2:3 in
favor of winning ?
explain using probabilities.
Yefim S. answered 04/29/21
Math Tutor with Experience
Probability to win in first game P1 = 4/(3 + 4) = 4/7
Probability to win in 2nd game P2 = 2/(2 + 3) = 2/5
4/7 = 20/35 > 14/35 = 2/5.
So I will pay 1st game because more chance to win
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