Kyra J.

asked • 04/26/21

Thinking Probability Question

1.Marie is playing a board game and

can win if she rolls a sum of either 6 or 8 or

doubles with a standard pair of dice. What

are the odds against Marie winning on a

given throw?

1 Expert Answer

By:

Paul M. answered • 04/26/21

Tutor
5.0 (39)

BS Mathematics, MD

Kyra J.

Hi thank you so much, so would the answer be 8/15? I did P(A) = 14/36 -> 7:18, used P(A) = h / k+h, odds in favour = 7 (h) : 8 (k) -> P(A) = 7 / 8+7 = 7/15, P(A) = 1 - 7/15 = 8/15 -> 8:15.
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04/26/21

Kyra J.

I realized that it was supposed to be like this, P(A) = 14/36 = 7/18, P(A') = 1-7/18 = 11/18, then use A = h/k-h, odds in favour = 11 = h / 18 = k, 11/18-11 = 11/7. But what I don't understand is that you are finding the odds against, I always did that with all other questions like this and got the right answer, but not this one
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04/28/21

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