
Freda A. answered 04/13/21
Experienced Tutor Specializing in Chemistry and Calculus
Here you would use Charles' Law: V1 V2
---- = ----
T1 T2
Here:
V1= 568 mL V2 = unknown (or what you're trying to find)
T1 = 25°C T2 = -25°C
Both T1 and T2 must be converted to Kelvin. To do that, you just add 273.15 to each of the temperatures making T1 and T2:
T1 = 298.15 K and T2 = 248.15 K
Then just plug in everything to the formula and you get:
568 mL V2 ----------->1.905 mL/K = (0.00403K)·V2 Making V2 = 472.7 mL or 473 mL
------------- = ---------------
298.15 K 248.15 K
This calculation makes sense because as
temperature decreases, so does volume