Here you would use Charles' Law: *V*_{1 }* V*_{2}

---- = ----

*T*_{1}* T*_{2}

Here:

V_{1}= 568 mL V_{2} = unknown (or what you're trying to find)

T_{1 }= 25°C T_{2} = -25°C

Both T_{1 }and T_{2} must be converted to Kelvin. To do that, you just add 273.15 to each of the temperatures making T_{1 }and T_{2}:

T_{1 }= 298.15 K and T_{2} = 248.15 K

Then just plug in everything to the formula and you get:

568 mL* V*_{2 } ----------->1.905 mL/K = (0.00403K)·*V*_{2 } Making *V*_{2 }= 472.7 mL or 473 mL

------------- = ---------------

298.15 K* * 248.15 K

This calculation makes sense because as

temperature decreases, so does volume