
Flora H.
asked 03/18/21physics question (answer is given but idk how to get to these answers)
A sled with two riders have a combined mass of 150.0 kg. They slide down a 12.0 m high hill and then across a frozen lake that is 60.0 m in diameter. The frictional force is a constant 200.0 N for the entire length of the run (both down the slope and then across the frozen lake).
a. Find the speed of the sled at the bottom of the hill. [8.67 m/s]
1 Expert Answer
The initial energy = 150*g*12 due to the 12m hill. 200*d of that energy is lost due to friction traveling to the bottom of the hill where d is the sliding distance to the bottom. The remaining energy of .5(150g)v2 is used up sliding the 60 meters * 200 N across the lake where v is the velocity at the bottom of the hill. So, 60*200=.5*150gv2 yielding v= 4.039 m/s (regardless of the answer you were given)
Still looking for help? Get the right answer, fast.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Sidney P.
I don't know either. I tried total ME = initial GPE = 17,640J, frictional loss across lake = 12,000J, so KE at bottom = 12,000j which yields speed of 12.6 m/s.03/18/21