At a certain temperature, an equilibrium mixture in a 1.00 L container consists of 0.245 M H2(g), 0.199 M I2(g), and 1.563 M HI(g).

Question

(a) Calculate KC for H2(g) + I2(g) ⇌ 2HI(g); (b) An additional 0.500 mol of H2(g) is added to the container. Calculate the new equilibrium concentrations.

Answer 1

Almost the same question as you posted earlier

a)

H₂(g) + I₂(g) <==> 2HI(g)

0.245...0.199........1.563......Equilibrium [ ]

Kc = [HI]² / [H₂][I₂]

Plug in the values and calculate Kc, just as I did in my previous answer.

b)

H₂(g) + I₂(g) <==> 2HI(g)

0.745...0.199........1.563

-x..........-x.............+2x......C

0.745-x....0.199-x....1.563+2x

Use the value of Kc determined in (a) above and solve for x and use to determine new concentrations of each species.