At 700 K, an equilibrium mixture of gases was found to contain 0.0215 M H2, 0.00158 M I2, and 0.0487 M HI. Calculate KC for H2(g) + I2(g) ⇌ 2HI(g) at 700 K.

Answer 1

H₂(g) + I₂(g) <==> 2HI(g)

0.0215...0.00158.....0.0487....Equilibrium [ ]

Kc = [HI]² / [H₂][I₂] = (0.0487)² / (0.0215)(0.00158)

Kc = 69.8