Jen S.

asked • 02/15/21

At 377 °C, KC = 0.0111 M for PCl5(g) ⇌ PCl3(g) + Cl2(g).

At 377 °C, KC = 0.0111 M for PCl5(g) ⇌ PCl3(g) + Cl2(g). Into a 2.00 L flask are placed 0.120 mol PCl5, 0.0600 mol PCl3, and 0.0400 mol Cl2. Are the contents of the flask at equilibrium? If not, which way will the reaction proceed?

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