The centripetal force is what is making the motorcycle turn and that force is provided by friction. F=mv2/r = 142*19.32/76= 696 Newtons
KM J.
asked • 12/20/20A 142 kg motorcycle is driving around a turn with a radius of 76 m at a constant speed of 19.3 m/s.
A 142 kg motorcycle is driving around a turn with a radius of 76 m at a constant speed of 19.3 m/s. What is the minimum force of friction required to prevent the cycle from sliding off of the road?
Follow
•
1
Add comment
More
Report
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
