A car is driving around a turn with a radius of 22.2 m.

Question

A car is driving around a turn with a radius of 22.2 m. If the coefficient of friction between the tires and the road is 1.38, what is the maximum speed the car can maintain around the turn without slipping?

Answer 1

F = mv²/r = umg thus v= sqrt(ugr)= sqrt(1.38*9.81*22.2)= 17.3 meters