Gina V.

asked • 11/30/20

really need help with derivatives

Particle P moves along the x-axis so that its position at time t>0 is given by xP(t)= (e^(2−t)−2t) / (e^(2−t)+3t). A second particle, particle Q , also moves along the x -axis so that its position at time t is given by xQ(t)=t^3−3t^2+5 .


a) Show that the velocity of particle P at time t is given by vP(t)= −5te^(2−t)−5e^(2−t) / (e^(2−t)+3t)^2 .


b) At time t=2 , particle Q is at rest. At time t=2 , is particle P moving toward particle Q or away from particle Q ? Explain your reasoning.


c) The acceleration of particle Q is given by aQ(t) . Find the value of aQ(2) .


d) Describe the position of particle P and the position of particle Q as t approaches infinity. How did you get to your answers.


1 Expert Answer

By:

Jeffrey C. answered • 11/30/20

Tutor
4.8 (6)

Experienced High School Tutor Specializing in Math

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