
Patrick B. answered 09/19/20
Math and computer tutor/teacher
The given is:
p->q v [ (p v ~q v p) v ~r ] =
associative/commutative:
p->q v [ (~q v (p v p)) v ~r] =
p->q v [ ~q v p v ~r ] =
implication identity:
~p v q v [ ~q v p v ~r ]
associative/commutative:
(~p v p) v (q v ~q) v ~r
X or ~X MUST be true:
True v True v ~r
True