
Christopher J. answered 09/18/20
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(∃x ∈ R)(∀y ∈ Q)(x+y < 0)
Fizaa A.
asked 09/18/20What would be the negation of the statement ?
Christopher J. answered 09/18/20
Berkeley Grad Math Tutor (algebra to calculus)
Try
(∃x ∈ R)(∀y ∈ Q)(x+y < 0)
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