C H. answered 08/20/20
Patient and Knowledgeable Math Tutor
A critical point is stable if the eigenvalues of Jacobian are both real and negative or complex and the real parts are negative.
At point A, the Jacobian is
|-π 0|
|0 π|.
The eigenvalues of this Jacobian are ±π. One eigenvalue is positive. Therefore, point A is not stable.
For the rest points, you can do it in a similar way.