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Asked • 29d

A red ball is thrown down with an initial speed of 1 m/s from a height of 27 meters above the ground.

A red ball is thrown down with an initial speed of 1 m/s from a height of 27 meters above the ground. Then, 0.7 seconds after the red ball is thrown, a blue ball is thrown upward with an initial speed of 24.7 m/s, from a height of 0.8 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.


1)What is the speed of the red ball right before it hits the ground?


2)How long does it take the red ball to reach the ground?


3)What is the maximum height the blue ball reaches?


4)What is the height of the blue ball 1.8 seconds after the red ball is thrown?


5)How long after the red ball is thrown are the two balls in the air at the same height?


1 Expert Answer

By:

Davinder S.

somehow the answer to 4th is incorrect.
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29d

Richard B.

tutor
I will check it later. Thanks for the review
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28d

Davinder S.

yeah, thanks so much for the help and time
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28d

Richard B.

tutor
Yes, I has a math error in #4. I forgot to square the t (1.1 squared) in the delta x equation. Answer came out to 22.2 meters
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28d

Davinder S.

thanks so much for the help sir.
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27d

Richard B.

tutor
You are definitely welcome and this was definitely not an easy problem
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27d

Davinder S.

i agree! Thanks
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25d

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