Determine the volume occupied by 0.582 moles of a gas at 15°C if the pressure is 622 mmHg.

Answer 1

We will use the Ideal Gas Law: PV = nRT. Because I will be using the R constant of 0.0821 L atm/moles K, we will put all units in these terms.

First, write down what you know:

P = 622 mmHg x 1 atm/ 760 mm HG = 0.818 atm

V = ?

n = 0.582 moles

R = 0.0821 L atm/moles K

T = 15 C + 273 = 288 K

Solve for Volume:

V = nRT/P = 0.582 moles(.0821 L atm/moles K)(288 K)/0.818 atm = 16.8 L