According to the following balanced reaction, how many grams of NO are formed from 388 grams of NO2 if there is plenty of water present? 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g) (Please help Urgent)

Question

Formula: 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

Answer 1

This is a simple mass to mass stoichiometry problem. You need to convert to moles, use the mole ratio, then convert back to grams.

388 g NO₂ (1 mol NO₂/ 46.01 g NO₂) (1 mol NO / 3 mol NO₂) (30.01 g NO / 1 mol NO) = 84.4 g NO