The brute force way is to take the derivative twice and set the second derivative to zero. This will find the time of maximum growth which happens at 9200/2 (Half of the carrying capacity.)
Another way is to write the logistic differential equation for your situation:
dG/dt = .121(G)(9200-G)
Take the second derivative
d2G/dt2 = d/dt(dG/dt) = (-.121G + (9200-G)(.121)) dG/dt by product rule and chain rule.
This is zero when G = (9200 -G) or G = 9200/2