
L. Marizza B. answered 11/14/19
Presidential Award in Mathematics and 20+ yrs of teaching Calculus
Since sin(2x) = 2sin(x)cos(x) then tan(x)sin(2x) = tan(x)2sin(x)cos(x). Now the trick is to write tan(x) = sin(x)/cos(x). So
tan(x)sin(2x) = sin(x)/cos(x) × 2 sin(x) cos(x)
Since the cos(x)'s cancel, we are left with
2sin 2(x)