Inequality word problem

Question

A cashier in a movie box sold 100 more adult admission tcikets that are at $10.50 each, than children tickets at $8.00 each. What is the minimum number of each type of tickets that the cashier has to sell for the total receipts to be at least $2530? Solve the problem with an inequality and graph.

I attempted the problem, and got 80 children tickets and 180 adult tickets. I just didn't know how to write this as an inequality or graph it.

Answer 1

A= # of Adult tickets

C=# of kids tickets

A=C+100

10.50A + 8C ≥ 2530

Now just solve the inequality to get as you did C≥80

and A = 100 +C, whatever value you use for C.

The graph will have C as the abscissa and Revenue as the ordinate.